9th Class Physics Chapter 1 Online Test: 25 MCQs with Answers

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This 9th class physics chapter 1 online test covers Chapter 1 of the Class 9 Physics course, Physical Quantities and Measurements. It has 25 multiple-choice questions, shown one at a time, and it marks itself as soon as you finish. There is no timer and no sign-up. When you press finish you get your score, and every question is shown again with your answer, the correct option and a short explanation of why that option is right. An Urdu medium version of the same test is given further down this page.

What Chapter 1 Covers

The questions are spread across the whole chapter rather than one section, so the test is a fair check of whether you are ready for a class test or the annual paper:

  • Base and derived quantities — which of the seven are base units, and which SI base unit already carries a prefix in its name.
  • Prefixes and scientific notation — femto, micro and milli, converting between them, and writing numbers such as 0.000000000052 m in standard form.
  • Vernier callipers — least count, main scale and vernier scale readings, and zero error on either side of the zero mark.
  • Screw gauge — pitch, circular scale divisions, least count, and taking a sleeve plus circular scale reading.
  • Significant figures and rounding — how many are in 0.0034 m, and rounding a value to two significant figures.
  • Errors and precision — systematic error from a badly calibrated balance, random error from repeated readings, and why results can be precise without being accurate.
  • Practical measurement — avoiding parallax in a measuring cylinder, stacking coins to find the thickness of one, and timing several oscillations of a pendulum.

Revise These Before You Start

Most marks in this chapter are lost on the same few points. Read through these once before attempting the test:

  • Least count of a vernier callipers = 1 main scale division ÷ number of vernier divisions, which gives 0.01 cm on a standard instrument.
  • Least count of a screw gauge = pitch ÷ circular scale divisions. A pitch of 0.5 mm with 50 divisions gives 0.01 mm.
  • Reading = main scale reading + (least count × coinciding division), then subtract the zero error with its sign.
  • A positive zero error is subtracted and a negative zero error is added. Getting the sign the wrong way round is the most common error in this chapter.
  • Zeros used only to fix the decimal point are not significant, so 0.0034 m has two significant figures.
  • Precision means readings agree with each other; accuracy means they agree with the true value. A systematic error keeps results precise but wrong.

How the Test Works

  • 25 questions, one at a time, with Next and Previous buttons.
  • No timer, so you can work a numerical out on paper before answering.
  • Automatic marking the moment you finish.
  • Answer review with the correct option and an explanation for every question.
  • Retake as many times as you like, and your score is not stored anywhere.

Start the Chapter 1 Online Test

Chapter 1 is where most Class 9 students lose easy marks, because the questions look simple but depend on the least count and the sign of the zero error. Keep a pen and rough paper beside you: the numerical questions are quick, but they are much easier to get right written down than in your head. Aim for 20 out of 25 or better before you move on to the next chapter.

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Class 9 Physics Chapter 1 Online Test — Physical Quantities and Measurements

25 multiple-choice questions from Chapter 1 of the Class 9 Physics course, with automatic marking, an answer review and explanations.

1 / 25

The instrument that is most suitable for measuring the thickness of a few sheets of cardboard is a:

2 / 25

One femtometre is equal to:

3 / 25

Which one of the following is a non-physical quantity?

4 / 25

Two rods with lengths 12.321 cm and 10.3 cm are placed side by side. The difference in their lengths is:

5 / 25

Four students measure the diameter of a cylinder with Vernier Callipers. Which of the following readings is correct?

6 / 25

In a Vernier Callipers ten smallest divisions of the Vernier scale are equal to nine smallest divisions of the main scale. If the smallest division of the main scale is half a millimetre, the Vernier constant is:

7 / 25

Which one of the following is NOT a base physical quantity?

8 / 25

Which is the only SI base unit whose name already contains a prefix?

9 / 25

2000 μs expressed in milliseconds is:

10 / 25

The diameter of a hydrogen atom is about 0.000000000052 m. In scientific notation this is:

11 / 25

The value of (4 × 10³ kg) × (6 × 10⁶ m) is:

12 / 25

The value of (6 × 10⁶ m³) ÷ (2 × 10⁻² m²) is:

13 / 25

A micrometer screw gauge has a pitch of 0.5 mm and 50 divisions on its circular scale. Its least count is:

14 / 25

Using a screw gauge, the sleeve reading is 6.5 mm and the 25th circular scale division is in line with the main scale. The thickness of the sheet is:

15 / 25

A Vernier Callipers shows a main scale reading of 4.3 cm and its 4th Vernier division coincides with a main scale marking. The length of the object is:

16 / 25

If the zero of the Vernier scale lies on the right side of the zero of the main scale, the zero error is:

17 / 25

A student measures the height of ten identical coins stacked one above the other and divides it by ten. This is done mainly to:

18 / 25

While reading the volume of water in a measuring cylinder, the eye must be kept in line with:

19 / 25

A balance has not been properly calibrated, so every reading taken with it is slightly off by the same amount. This is an example of a:

20 / 25

Repeated measurements of the same quantity give slightly different values because of sudden changes in temperature and air currents. The best way to reduce this effect is to:

21 / 25

To find the time period of a simple pendulum accurately, the time for about thirty oscillations is measured and then divided by thirty. This is done to:

22 / 25

The number of significant figures in the measurement 0.0034 m is:

23 / 25

Rounded off to two significant figures, 4.55 × 10² m becomes:

24 / 25

A group of measurements lies very close to one another but far from the true value. These measurements are:

25 / 25

A line is measured with a metre rule calibrated in millimetres. The maximum uncertainty in this measurement is:

Your score is

0%

Chapter 1 Online Test — Urdu Medium

Urdu medium students can attempt the same Chapter 1 test with every question, option and explanation written in Urdu. It behaves exactly like the English test above: 25 questions one at a time, no timer, and a full answer review at the end.

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Class 9 Physics Chapter 1 Online Test (Urdu Medium) — Physical Quantities and Measurements

Urdu medium online test, 25 MCQs with instant result and explanations.

1 / 25

چند گتے کی شیٹوں کی موٹائی ماپنے کے لیے سب سے موزوں آلہ ہے:

2 / 25

ایک فیمٹو میٹر برابر ہے:

3 / 25

مندرجہ ذیل میں سے کون سی غیر طبیعی مقدار ہے؟

4 / 25

12.321 cm اور 10.3 cm لمبائی کی دو سلاخیں ساتھ ساتھ رکھی ہیں۔ ان کی لمبائی میں فرق ہے:

5 / 25

چار طلبہ ورنیئر کیلی پرز سے ایک سلنڈر کا قطر ناپتے ہیں۔ درج ذیل میں سے کون سی ریڈنگ درست ہے؟

6 / 25

ایک ورنیئر کیلی پرز میں ورنیئر سکیل کے دس کم ترین درجے مین سکیل کے نو کم ترین درجوں کے برابر ہیں۔ اگر مین سکیل کا کم ترین درجہ آدھا ملی میٹر ہو تو ورنیئر کونسٹنٹ ہے:

7 / 25

مندرجہ ذیل میں سے کون سی بنیادی طبیعی مقدار نہیں ہے؟

8 / 25

وہ واحد SI بنیادی یونٹ کون سا ہے جس کے نام میں پہلے سے ہی پری فکس شامل ہے؟

9 / 25

2000 μs کو ملی سیکنڈ میں ظاہر کیا جائے تو ہوگا:

10 / 25

ہائیڈروجن ایٹم کا قطر تقریباً 0.000000000052 m ہے۔ سائنسی نوٹیشن میں یہ ہے:

11 / 25

(4 × 10³ kg) × (6 × 10⁶ m) کی قیمت ہے:

12 / 25

(6 × 10⁶ m³) ÷ (2 × 10⁻² m²) کی قیمت ہے:

13 / 25

ایک مائیکرومیٹر سکریو گیج کا پچ 0.5 mm ہے اور اس کے سرکلر سکیل پر 50 درجے ہیں۔ اس کا لیسٹ کاؤنٹ ہے:

14 / 25

ایک سکریو گیج میں سلیو ریڈنگ 6.5 mm ہے اور سرکلر سکیل کا 25 واں درجہ مین سکیل کے سامنے ہے۔ شیٹ کی موٹائی ہے:

15 / 25

ایک ورنیئر کیلی پرز میں مین سکیل ریڈنگ 4.3 cm ہے اور ورنیئر کا چوتھا درجہ مین سکیل کے کسی نشان سے مل رہا ہے۔ جسم کی لمبائی ہے:

16 / 25

اگر ورنیئر سکیل کا صفر مین سکیل کے صفر کی دائیں جانب ہو تو زیرو ایرر:

17 / 25

ایک طالب علم دس ایک جیسے سکے ایک کے اوپر ایک رکھ کر ان کی کل اونچائی ناپتا ہے اور پھر اسے دس پر تقسیم کرتا ہے۔ ایسا بنیادی طور پر کیوں کیا جاتا ہے؟

18 / 25

پیمائشی سلنڈر میں پانی کا حجم پڑھتے وقت آنکھ کس کے برابر رکھنی چاہیے؟

19 / 25

ایک ترازو درست طور پر کیلیبریٹ نہیں کیا گیا، اس لیے اس سے لی گئی ہر ریڈنگ ایک ہی مقدار سے غلط آتی ہے۔ یہ کس کی مثال ہے؟

20 / 25

ایک ہی مقدار کی بار بار پیمائش پر ٹمپریچر اور ہوا کے جھونکوں کی اچانک تبدیلی سے مختلف قیمتیں ملتی ہیں۔ اس اثر کو کم کرنے کا بہترین طریقہ ہے:

21 / 25

سادہ پینڈولم کا ٹائم پیریڈ درست معلوم کرنے کے لیے تقریباً تیس جھولوں کا وقت ناپ کر تیس پر تقسیم کیا جاتا ہے۔ ایسا کیوں کیا جاتا ہے؟

22 / 25

پیمائش 0.0034 m میں نمایاں ہندسوں کی تعداد ہے:

23 / 25

4.55 × 10² m کو دو نمایاں ہندسوں تک رواؤنڈ آف کیا جائے تو ہوگا:

24 / 25

کچھ پیمائشیں ایک دوسرے کے بہت قریب ہیں لیکن حقیقی قیمت سے بہت دور ہیں۔ یہ پیمائشیں ہیں:

25 / 25

ملی میٹر میں درجہ بند میٹر رول سے ایک لائن ناپی جاتی ہے۔ اس پیمائش میں زیادہ سے زیادہ غیر یقینی ہے:

Your score is

0%

Mistakes Students Make in This Chapter

When you check your answer review, see whether any of your wrong answers came from these. They account for most of the marks lost in this chapter:

  • Treating every zero in a number as a significant figure.
  • Forgetting the sign of the zero error, or ignoring it entirely.
  • Multiplying when converting a smaller prefix into a larger one instead of dividing, for example with 2000 μs into milliseconds.
  • Confusing precision with accuracy when a question describes readings that are close together but far from the true value.
  • Timing a single swing of a pendulum instead of ten or twenty and dividing, which multiplies your reaction-time error.

What to Do After the Test

Do not close the page as soon as you see your score. Read the explanation under every question you got wrong, then open that topic in your textbook and work through the solved example beside it. Write the questions you missed on a single sheet and attempt the test again the next day: the second score tells you what you have actually learned, while the first only tells you what you recognised. If you scored below 15, work through the chapter again before moving on, because the later chapters in Physics build directly on this one.

Frequently Asked Questions

What is the least count of a Vernier Callipers?

On the standard instrument used in Class 9, one main scale division is 1 mm and the vernier scale has 10 divisions, so the least count is 0.1 mm, or 0.01 cm. It is the smallest length the instrument can measure reliably.

How do I handle zero error in a measurement?

Close the jaws or screw first and note where the zero marks sit. If the vernier zero lies to the right of the main scale zero, the error is positive and you subtract it from every reading. If it lies to the left, the error is negative and you add it.

Why do we time ten oscillations of a pendulum instead of one?

Your reaction time when starting and stopping the watch is roughly the same whether you time one swing or ten. Timing ten and dividing by ten spreads that error across ten readings, so the time period you calculate is far closer to the true value.

Related Class 9 Physics Resources

Work through the Chapter 1 exercise short questions for written practice. The Chapter 1 constructive questions cover the longer, reasoning-based answers. You can also browse all Class 9 Physics exercise short questions and constructive questions, or open the Class 9 Physics section, which brings notes, test papers, online papers, guess papers and past papers together chapter by chapter.

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